SOLUTION: Can I please have help on this problem thank you! Graphically determine the solution to the systems 1. y=2x^2-12x+19,y=2x-1 2. y=x^2-2x+8,y=x-7 3. y=x^2+5x-7, y=2x^2=2x+3

Algebra ->  Graphs -> SOLUTION: Can I please have help on this problem thank you! Graphically determine the solution to the systems 1. y=2x^2-12x+19,y=2x-1 2. y=x^2-2x+8,y=x-7 3. y=x^2+5x-7, y=2x^2=2x+3      Log On


   



Question 1195106: Can I please have help on this problem thank you!
Graphically determine the solution to the systems
1. y=2x^2-12x+19,y=2x-1
2. y=x^2-2x+8,y=x-7
3. y=x^2+5x-7, y=2x^2=2x+3

Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Graphically determine the solution to the systems
1. y=2x^2-12x+19,y=2x-1
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For the parabola y = 2x^2-12x+19, pick values for x and find y.
Plot the points and draw the curve thru them.
y = 2x-1 is a straight line, so 2 points are needed
The intersections are the solutions.
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There are several FREE graph softwares online.
I use www.padowan.dk
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2. y=x^2-2x+8,y=x-7
Same as #1
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3. y=x^2+5x-7, y=2x^2=2x+3
If you meant x^2+5x-7, y=2x^2-2x+3 it's 2 parabolas.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
1. y=2x%5E2-12x%2B19,y=2x-1

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C2x%5E2-12x%2B19%2C+2x-1%29+
as you can see, intersection points are (2,3) and (5,9)
so, solution is:
x=2,x=3
y=5,y=9


2. y=x%5E2-2x%2B8,y=x-7
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2Cx%5E2-2x%2B8%2C+x-7%29+
there is no intersection point(s), so there is no real number solution

3. y=x%5E2%2B5x-7, y=2x%5E2%2B2x%2B3 (assuming you have that)
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2Cx%5E2%2B5x-7%2C+2x%5E2%2B2x%2B3%29+

as you can see, there is no intersection point(s), so there is no real number solution