SOLUTION: 3. Sketch the following parabolas. Write whether the roots are real or complex numbers. a. f(x) = 8x^2 +3

Algebra ->  Graphs -> SOLUTION: 3. Sketch the following parabolas. Write whether the roots are real or complex numbers. a. f(x) = 8x^2 +3      Log On


   



Question 118380: 3. Sketch the following parabolas. Write whether the roots are real or complex numbers.

a. f(x) = 8x^2 +3

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
From the quadratic formula
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

the discriminant consists of all of the terms in the square root. So the discriminant is

D=b%5E2-4ac

the discriminant tells us how many solutions (and what type of solutions) we can expect for any quadratic. If the discriminant is greater than zero, then we will have 2 real solutions. If the discriminant is equal to zero, then we will have one real solution. Finally, if the discriminant is less than zero, then we will have 2 imaginary solutions.

So let's use the discriminant to find the number and type of solutions y=8x%5E2%2B3 has:


D=0%5E2-4%2A8%2A3 Plug in a=8, b=0, c=3

D=0-4%2A8%2A3 Square 0 to get 0

D=0-96 Multiply -4*8*3 to get -96

D=-96 Combine 0 and -96 to get -96


Since the discriminant equals -96 (which is less than zero), this means there are two imaginary solutions



Notice if we graph y=8x%5E2%2B3 (to graph, just plot a few points), we get

+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+8x%5E2%2B3%29+

and we can see that the graph does not cross the x-axis, so there are two imaginary solutions.