SOLUTION: Sketch the graph, using the function and three points: two roots and the turning point. a. f(x) = x^2 + 6x - 16

Algebra ->  Graphs -> SOLUTION: Sketch the graph, using the function and three points: two roots and the turning point. a. f(x) = x^2 + 6x - 16      Log On


   



Question 118377: Sketch the graph, using the function and three points: two roots and the turning point.

a. f(x) = x^2 + 6x - 16

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
To find the roots of f%28x%29=x%5E2%2B6x-16, set the entire function equal to zero
x%5E2%2B6x-16=0


%28x%2B8%29%28x-2%29=0 Factor the left side (note: if you need help with factoring, check out this solver)



Now set each factor equal to zero:
x%2B8=0 or x-2=0

x=-8 or x=2 Now solve for x in each case


So the roots are

x=-8 or x=2



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Now let's find the vertex (ie the turning point)

To find the x coordinate of the vertex, simply use this formula x=-b%2F2a

Looking at f%28x%29=x%5E2%2B6x-16, we can see that a=1 and b=6.

x=-6%2F2%281%29 Plug a=1 and b=6 into the formula.

x=-6%2F2 Multiply

x=-3 Reduce


So the x-coordinate of the vertex is x=-3


To find the y coordinate, simply plug in x=-3 into f%28x%29=x%5E2%2B6x-16 to evaluate f%28-3%29




Let's evaluate f%28-3%29


f%28x%29=x%5E2%2B6x-16 Start with the given function.


f%28-3%29=%28-3%29%5E2%2B6%28-3%29-16 Plug in x=-3. In other words, replace each x with -3.


f%28-3%29=%289%29%2B6%28-3%29-16 Evaluate %28-3%29%5E2 to get 9.


f%28-3%29=%289%29%2B-18-16 Multiply 6 and -3 to get -18


f%28-3%29=-25 Now combine like terms

So the vertex is: (-3,-25)



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Summary:

So our roots are

x=-8 or x=2

and our vertex is at the point

(-3,-25)



Now let's graph these three points




Now connect the points with a parabola (note: the more points you plot the more accurate the graph is)