Question 1183052: Find the vertex and Y and X intercepts of the function F(x)=-x^2+4x-3.
is the F(x) considered they y? please and thank you
Found 3 solutions by MathLover1, MathTherapy, josgarithmetic: Answer by MathLover1(20849) (Show Source): Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website! Find the vertex and Y and X intercepts of the function F(x)=-x^2+4x-3.
is the F(x) considered they y? please and thank you
It's NOT NECESSARY, at ALL, to complete the square, as the other person did, in order to get the vertex.
- x2 + 4x - 3
The x-coordinate of the vertex is where , or, where: 
The y-coordinate of the vertex is where 
Therefore, vertex, or 
For the y-intercept, substitute 0 for x, and solve for f(0), or y, as follows: 

For the x-intercepts, substitute 0 for f(x), or y, and solve for x, as follows: 
Substituting 3x + x for 4x gives us:
0 = - x(x - 3) + 1(x - 3)
0 = (- x + 1)(x - 3)
0 = - x + 1 OR 0 = x - 3
x = 1 OR 3 = x ====> x = 3
Answer by josgarithmetic(39617) (Show Source):
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