SOLUTION: I have a graphing problem I need help with please Quuestion: https://imgur.com/a/uzKVvfA

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Question 1181844: I have a graphing problem I need help with please
Quuestion: https://imgur.com/a/uzKVvfA

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Do you see an "8" and a "4" in there?
x%5E2%2B12x%2B32=0

You know this is %28x%2B4%29%28x%2B8%29=0, so your x-axis intercepts are easily known. The vertex will occur at x=-6. You can use these facts and others to sketch your graph.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

I have a graphing problem I need help with please
Quuestion: https://imgur.com/a/uzKVvfA
matrix%281%2C3%2C+x%5E2+%2B+12x+%2B+32%2C+%22=%22%2C+0%29
h, or x-coordinate of vertex occurs where 
k, or y-coordinate of vertex:  
With (h, k) being (- 6, 4), we get: ============
                                    |   x    y |
                                    |- 10      |
                                    |-  8      |
                                    |-  6  - 4 |
                                    |-  4      |
                                    |-  2      |
                                    ============
Populating the y-slots above or below the vertex, 
              (- 6, - 4) gives us:  ============
                                    |   x    y |
                                    |- 10   12 |
                                    |-  8    0 |
                                    |-  6  - 4 |
                                    |-  4      |
                                    |-  2      |
Below the VERTEX, we have the SAME y-coordinates 
we just found, ABOVE. This gives us:============
                                    |   x    y |
                                    |- 10   12 |
                                    |-  8    0 |
                                    |-  6  - 4 |
                                    |-  4    0 |
                                    |-  2   12 |  
                                    ============
You now have the vertex, (- 6, - 4), plus 2 points on EITHER side of the vertex. 

In addition, if you look you'll see the solutions to the quadratic: the points on the x-axis, or the roots,
which are: - 8, from point (- 8, 0), and - 4, from the point, (- 4, 0)