|
Question 1181614: What is the solution to the system?
-x-2y=2
2x+3y=-3
Found 6 solutions by mananth, MathTherapy, josgarithmetic, ikleyn, CPhill, n2:
Answer by mananth(16949)   (Show Source):
You can put this solution on YOUR website! -x-2y=2 -----------------1
2x+3y=-3------------------2
multiply (1) by 2
we get
-2x-4y=-4 Add this to eq (2)
2x+3y=-3
-y =-7
y=7
plug y in eq(1)
-x -2*7=2
-x= 16
x= -16
solution ( -16,7)
Answer by MathTherapy(10803)  (Show Source):
Answer by josgarithmetic(39792)  (Show Source):
Answer by ikleyn(53746)  (Show Source):
You can put this solution on YOUR website! .
What is the solution to the system?
-x-2y=2
2x+3y=-3
~~~~~~~~~~~~~~~~~
The solution in the post by @mananth is INCORRECT.
Easy check shows that his answer (-16,7) does not satisfy first equation.
I came to bring a correct solution.
Your starting equations are
-x - 2y = 2 (1)
2x + 3y = -3 (2)
Multiply equation (1) by 2 and add with the second equation. You will get
-y = 1, y = -1.
Then from equation (1),
x = -2y - 2 = -2*(-1) - 2 = 2 - 2 = 0.
ANSWER. There is a unique solution x = 0, y = -1.
CHECK. You may check it on your own, that my answer satisfies both given equations.
Solved correctly.
Answer by CPhill(2189)  (Show Source):
You can put this solution on YOUR website! -x-2y=2 -----------------1
2x+3y=-3------------------2
multiply (1) by 2
we get
-2x-4y=-4 Add this to eq (2)
2x+3y=-3
-y =-7
y=7
plug y in eq(1)
-x -2*7=2
-x= 16
x= -16
solution ( -16,7)
Answer by n2(78) (Show Source):
You can put this solution on YOUR website! .
What is the solution to the system?
-x-2y=2
2x+3y=-3
~~~~~~~~~~~~~~~~~~~~~~~~~~~
@CPhill copy-pasted the solution by @mananth and placed it under his own name (even without acknowledgment).
Both "solutions" by @CPhill and by @mananth are identical and both are WRONG,
since they do not satisfy the original equations.
For correct solution, see the post by @ikleyn at this spot.
Ignore both posts by @CPhill and @mananth - their solutions both are irrelevant to the given problem.
|
|
|
| |
