SOLUTION: Find the equation of the line perpendicular to y = x -2 that passes through the point (0,4).

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Question 1180492: Find the equation of the line perpendicular to y = x -2 that passes through the point (0,4).
Found 2 solutions by Theo, josgarithmetic:
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the perpendicular line will have a slope that is the negative reciprocal of the slope of the line that it is perpendicular to.

the line that it is perpendicular to is y = x - 2.

the slope of that line is 1.

the negative reciprocal of that slope is -1/1 = -1.
the slope intercept form of the perpendicuoar line is y = -x + b.

the perpendicular line goes thorough the point (0,4),.

the equation becomes y = -x + 4.
-1 is the slope.
4 is the y-intercept.

the y-intercept is the value of y when the vlaue os x = 0.

at the poijt (0,4), the value of x = 0 and the value of y = 4.

that makes y equal to the y-intercept.

your two equqtions are:

y = x - 2
y = -2 + 4

these lines can be graphed as shown below.








Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
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Find the equation of the line perpendicular to y = x -2 that passes through the point (0,4).
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Slope for the wanted line, -1. Now, just plug into/ use slope intercept equation form and finish.

y=-x%2B4