SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x2 + y2 + 6x + 4y = 3
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-> SOLUTION: Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x2 + y2 + 6x + 4y = 3
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Question 1179452: Complete the square and write the equation in standard form. Then give the center and radius of the circle.
x2 + y2 + 6x + 4y = 3 Found 2 solutions by josgarithmetic, Edwin McCravy:Answer by josgarithmetic(39617) (Show Source):
x2 + y2 + 6x + 4y = 3
Get the x-terms next to each other.
Get the y-terms next to each other.
Skip a space after the x terms and after the y terms:
x2 + 6x + y2 + 4y = 3
Complete the square out to the side or on scratch paper.
1. Multiply the coefficient of x by 1/2.
2. Square what you get.
3. Add that to the space after the x-terms on the left and also
add it to the right side.
x2 + 6x + 9 + y2 + 4y = 3 + 9
1. Multiply the coefficient of y by 1/2.
2. Square what you get.
3. Add that to the space after the y-terms on the left and also
add it to the right side.
x2 + 6x + 9 + y2 + 4y + 4 = 3 + 9 + 4
Factor the first three terms on the left side.
Factor the last three terms on the left side.
Combine the numbers on the right side.
(x + 3)(x + 3) + (y + 2)(y + 2) = 16
Notice that they factored as the same factor twice, so write
them as squares:
(x + 3)2 + (y + 2)2 = 16
Compare that to what you should have memorized.
(x - h)2 + (y - k)2 = r2 where (h,k) is the center and r is the radius.
Set corresponding things equal to each other and solve
-h = +3 -k = +2 r2 = 16
h = -3 k = -2 r = √16
r = 4
Substitute for all letters except x and y
Simplify:
Center = (h,k) = (-3,-2), radius = r = 4
Edwin