SOLUTION: A landscape designer has to design a retangular pad of concrete at the centre of a rock garden. The length must be less than or equal to twice the width; the perimeter must be less

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Question 117470: A landscape designer has to design a retangular pad of concrete at the centre of a rock garden. The length must be less than or equal to twice the width; the perimeter must be less than or equal to 40m; and the area must be greater than or equal to 60m^2
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
A landscape designer has to design a retangular pad of concrete at the centre of a rock garden. The length must be less than or equal to twice the width; the perimeter must be less than or equal to 40m; and the area must be greater than or equal to 60m^2

>>......The length must be less than or equal to twice the width...<<

L < 2W

>>...the perimeter must be less than or equal to 40m...<<

Perimeter = 2L + 2W < 40

>>......and the area must be greater than or equal to 60m^2...<<

Area = LW > 60

So we have these three facts:

1.   L < 2W
2.   2L + 2W < 40
3.   LW > 60

Solve #2 for 2W:  2W < 40 - 2L

Putting this together with #1: 

L < 2W < 40 - 2L

Add 2L to all three sides:    

3L < 2W + 2L < 40

So  
     3L < 40

4.   L < 40%2F3

Solve #3 for L:               

     L > 60%2FW

or 60%2FW < L 

Put that together with #4

60%2FW < L < 40%2F3 

So

60%2FW < 40%2F3
  
        60 < 40%2F3W

       180 < 40W

   180%2F40 < W  
  
      9%2F2 < W

or            W > 9%2F2 

So since L < 40%2F3 and  W > 9%2F2

The length must be less than or equal to 131%2F3 m.
The width must be greater than or equal to 41%2F2 m.

Edwin