Question 1174531: Line l is perpendicular to the graph of 2x + 3y = 5, and has the same x-intercept as the graph of 2x + 3y = 5. Find the standard form of the equation whose graph is l.
Found 2 solutions by Boreal, MathTherapy:
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! 2x+3y=5 is y=(-2/3)x+(5/3), with slope -2/3 and y-intercept (5/3). The x-intercept is when y=0 and is 2.5
The perpendicular line has slope 3/2, the negative reciprocal.
We know that a point on that line is (2.5, 0) from the first line.
point-slope formula y=y1=m(x-x1), m slope (x1, y1) point
y-0=(3/2)(x-2.5)
y=(3/2)x-3.75
or (3/2)x-y=3.75 and standard form 12x-8y=30
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Line l is perpendicular to the graph of 2x + 3y = 5, and has the same x-intercept as the graph of 2x + 3y = 5. Find the standard form of the equation whose graph is l.
Multiplying the above by LCD, 2, the standard form of the equation of Line 1 is: 
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