SOLUTION: I don´t understand... :(
Suppose that the function f is defined for all real numbers as follows.
f(x)= x^(2)+1 if x<1
2 if x=1
8-3x if x>1
Graph the function f. Then determ
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-> SOLUTION: I don´t understand... :(
Suppose that the function f is defined for all real numbers as follows.
f(x)= x^(2)+1 if x<1
2 if x=1
8-3x if x>1
Graph the function f. Then determ
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Question 1165263: I don´t understand... :(
Suppose that the function f is defined for all real numbers as follows.
f(x)= x^(2)+1 if x<1
2 if x=1
8-3x if x>1
Graph the function f. Then determine whether or not the function is continuous. Answer by solver91311(24713) (Show Source):
The domain of the given function is all real numbers, so for continuity you must have
So calculate and and see if they are equal or not.
The reason you don't have to worry about any other values in the domain is that each piece of the piecewise function is a polynomial with a restricted domain and all polynomials are continuous over their entire domain.
John
My calculator said it, I believe it, that settles it