We know that substituting a power of x into a power of x gives a power of
x, so we try to see if f(x)=xn gives a solution:
If so then try
f(x) = xn
then
f(f(x)) = f(xn) = (xn)n = xn² = x2
The one and only way that can be true for all x is if the exponents of x are
equal
So n²=2
or
So one solution is
Another solution is
Can there be other solutions???
Edwin