SOLUTION: the slope of the straight line ehich is both tangent and normal to the cuve 4x^3 = 27y^2 is a) ± 1 b) ±(1/2) c) ± (1/sqrt(2)) d) ± sqrt(2) and find the eq

Algebra ->  Graphs -> SOLUTION: the slope of the straight line ehich is both tangent and normal to the cuve 4x^3 = 27y^2 is a) ± 1 b) ±(1/2) c) ± (1/sqrt(2)) d) ± sqrt(2) and find the eq      Log On


   

Question 1143491: the slope of the straight line ehich is both tangent
and normal to the cuve 4x^3 = 27y^2 is
a) ± 1 b) ±(1/2) c) ± (1/sqrt(2)) d) ± sqrt(2)
and find the equation of the lines.
Found 3 solutions by Alan3354, Edwin McCravy, ikleyn:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Not clear what you mean.
--------------
Ikelyn might be correct, but
-----
It is not our job to figure out what you might mean.
It's incumbent upon you to make clear what it is you want to do.

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

As you can see from the graph of 4x³ = 27y²,



the only line that is tangent to the curve and also
normal to the curve is the x-axis.  The x-axis has
equation y = 0 and has slope 0, which is none of
the given answers.  Is there a mistake in copying 
something?  If so tell me about it in the note form
below and I'll get back to you by email.

Edwin

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

Edwin / Alan,

the meaning of this assignment is  (as I understand it)  that the straight line should be tangent to one branch

of the plot  (see  Edwin's graph)  and  AT  THE  SAME  TIME  be a normal to the other branch.


I myself will not work on it  (since I do not see nothing attractive/interesting/educational in it).

But if you are enthusiastic about it,  you may try.