SOLUTION: let. a, b, c, d be positive integers and (log( b)/log (a))=3/2 ,(log (d)/log (c))=5/4 ,if a-c=9 then b - d = .....

Algebra ->  Graphs -> SOLUTION: let. a, b, c, d be positive integers and (log( b)/log (a))=3/2 ,(log (d)/log (c))=5/4 ,if a-c=9 then b - d = .....      Log On


   



Question 1141585: let. a, b, c, d be positive integers and (log( b)/log (a))=3/2
,(log (d)/log (c))=5/4 ,if a-c=9 then b - d = .....

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
, where0 a, b, c, d are positive integers.





system%28a%5E3=b%5E2%2Cc%5E5=d%5E3%2Ca-c=9%29

Let a=p%5E2,b=p%5E3,c=q%5E3,d=q%5E5 and perhaps
p and q can be positive integers.  We will see.



system%28p%5E6=p%5E6%2Cq%5E20=q%5E20%2Cp%5E2-q%5E4=9%29

p%5E2-q%5E4=9

Factor the left side:

%28p-q%5E2%29%28p%2Bq%5E2%29=9

If those expressions in parentheses can be positive integers,
they can only be the unequal pair of factors of 9, which are
1 and 9. The p-q² is smaller, so it would be 1 and p+q² is
larger so it would be 9:

p-q%5E2=1, p%2Bq%5E2=9

system%28p-q%5E2=1%2Cp%2Bq%5E2=9%29

Add the equations:

2p=10
p=5

Subtract the equations:

-2q%5E2=-8
q%5E2=4
q=2

So we now see that p and q can be positive integers.

a=p%5E2,b=p%5E3,c=q%5E4,d=q%5E5

a=5%5E2,b=5%5E3,c=2%5E4,d=2%5E5

a=25,b=125,c=16,d=32

b-d=125-32

b-d=93

Edwin