SOLUTION: if line PQ passes through (1,2) and perpendicular to y=5x-1, determined the equation of PQ.
If the gradient of AB,is 15, 3,and line PQ is parrell to line AB,and passes through
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-> SOLUTION: if line PQ passes through (1,2) and perpendicular to y=5x-1, determined the equation of PQ.
If the gradient of AB,is 15, 3,and line PQ is parrell to line AB,and passes through
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Question 1140305: if line PQ passes through (1,2) and perpendicular to y=5x-1, determined the equation of PQ.
If the gradient of AB,is 15, 3,and line PQ is parrell to line AB,and passes through point (-4,5) for the equation of line AB Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The slope of a line perpendicular to line with slope 5 is -1/5 (negative reciprocal)
point slope formula y-y1=m(x-x1)
y-2=(-1/5)(x-1)
y=(-1/5)x+11/5 (1/5+2)
The slope of AB is 5; parallel lines have the same slope
y-5=5(x+4), note signs
y=5x+25
