SOLUTION: Describe the end behavior of the graph of the function.
f(x) = −5(8)^ x − 2
As x → −∞, f(x) → ? As x → ∞, f(x) → −∞
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-> SOLUTION: Describe the end behavior of the graph of the function.
f(x) = −5(8)^ x − 2
As x → −∞, f(x) → ? As x → ∞, f(x) → −∞
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Question 1137989: Describe the end behavior of the graph of the function.
f(x) = −5(8)^ x − 2
As x → −∞, f(x) → ? As x → ∞, f(x) → −∞ Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! 8 raised to any power is positive
Therefore, as x increases to infinity, 8^(x-2), increases to positive infinity, but -5*(8^(x-2)) increases to negative infinity.
as x goes to negative infinity, 8^(x-2) goes to 0, and -5*8^(x-2) goes to 0 from the negative side.
