SOLUTION: Could you help me with this problem? I need to graph this first: f(x)= x^2-4x+5 and then show the values on the table. x| -3 | -2 | -1 | 0 | 1 | 2 | 3

Algebra ->  Graphs -> SOLUTION: Could you help me with this problem? I need to graph this first: f(x)= x^2-4x+5 and then show the values on the table. x| -3 | -2 | -1 | 0 | 1 | 2 | 3       Log On


   

Question 1134484: Could you help me with this problem?
I need to graph this first: f(x)= x^2-4x+5 and then show the values on the table.

x| -3 | -2 | -1 | 0 | 1 | 2 | 3
f(x)| | | | | | |


Then name the domain and range.
Found 2 solutions by MathLover1, rothauserc:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
to graph this first:
f%28x%29=+x%5E2-4x%2B5 and then show the values on the table.
x|+-3 |+-2 | -1+| 0 | 1 | 2 | 3

f%28x%29| | | | | | |
if +x=-3
f%28-3%29=+%28-3%29%5E2-4%28-3%29%2B5=9%2B12%2B5=26
if +x=-2
f%28-2%29=+%28-2%29%5E2-4%28-2%29%2B5=4%2B8%2B5=17
if +x=-1
f%28-1%29=+%28-1%29%5E2-4%28-1%29%2B5=1%2B4%2B5=10
if +x=0
f%280%29=+%280%29%5E2-4%280%29%2B5=5
if +x=1
f%281%29=+%281%29%5E2-4%281%29%2B5=1-4%2B5=2
if +x=2
f%282%29=+%282%29%5E2-4%282%29%2B5=4-8%2B5=1
if +x=3
f%283%29=+%283%29%5E2-4%283%29%2B5=9-12%2B5=2

=> your table is
x|+-3 |+-2 | -1+| 0 | 1 | 2 | 3

f%28x%29|26 |17 | 10|5 |2 |1 |+2

plot all points and draw a parabola through:




Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
The graph of f(x)= x^2-4x+5 is
:
+graph%28+300%2C+200%2C+-4%2C+10%2C+-4%2C+27%2C+x%5E2+-4x+%2B5%29+
:
x f(x)
------
-3 26
-2 17
-1 10
0 5
1 2
2 1
3 2
:
domain is all real numbers
:
range is all positive real numbers greater than or equal to 1
:
Note the vertex of the parabola is (2,1)
: