SOLUTION: What is the equation of the line that passes through (-3, -1) and has a slope of 2/5? Put your answer in slope-intercept form.

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Question 1134073: What is the equation of the line that passes through (-3, -1) and has a slope of 2/5? Put your answer in slope-intercept form.
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation of the line that passes through (-3,-1) and has a slope of 2/5? Put your answer in slope-intercept form.
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Use y-y1 = m*(x-x1) where m = slope and (x1,y1) is the point
y+1 = (2/5)*(x+3)
y = (2/5)x + 6/5-1
y = (2/5)x + 1/5
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slope-intercept form is
y = mx + b
m = slope = 2/5
b = y-intercept = 1/5 or (0,1/5)

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

slope-intercept form: y=mx%2Bb where m is a slope and b is y-intercept
the equation of the line that passes through (-3, -1) and has a slope ofm=+2%2F5 will be:
y=mx%2Bb........plug in given data and find b
-1=%282%2F5%29%28-3%29%2Bb
-1=-6%2F5%2Bb
-1%2B6%2F5=b
-5%2F5%2B6%2F5=b
b=1%2F5
now we have a slope ofm=+2%2F5 and y-intercept b=1%2F5 and your
equation is:y=%282%2F5%29x%2B1%2F5