SOLUTION: find the value of 'a' for which the graph of the first equation is perpendicular to the graph of the second equation Exp: y=ax-5; 3y-4x=7

Algebra ->  Graphs -> SOLUTION: find the value of 'a' for which the graph of the first equation is perpendicular to the graph of the second equation Exp: y=ax-5; 3y-4x=7      Log On


   

Question 1121258: find the value of 'a' for which the graph of the first equation is perpendicular to the graph of the second equation
Exp: y=ax-5; 3y-4x=7
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
Solving the 2nd equation for y: +y+=+%284%2F3%29x%2B%287%2F3%29+
This is the slope-intercept form of the line, where the slope is 4/3.
Perpendicular lines will have slopes that are related by +m%5B2%5D+=+%28%28-1+%29%2F+m%5B1%5D%29+
so a = -1 / (4/3) = +highlight%28+-3%2F4+%29+