You can put this solution on YOUR website! One approach is to set the first to equal 0
x^4+(x-4)^4-82=0
x=3 can be see to be a solution
x=1 can also be seen to be a solution
This product of factors (x-3) and (x-1), or x^2-4x+3, can be divided into the expanded polynomial 2x^4-16x^3+96x^2-256x+174
or its equivalent of x^4-8x^3+48x^2-128x+87
to yield the quadratic x^2-4x+29, which is prime and the third factor of the original polyomial.
