SOLUTION: 2x +3y ≤ 6, x+4y ≤4, x ≥0,y ≥0.solve graphicalky

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Question 1120282: 2x +3y ≤ 6, x+4y ≤4, x ≥0,y ≥0.solve graphicalky
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388) About Me  (Show Source):
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
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The given system of inequalities is equivalent to 


    y <= %286+-+2x%29%2F3          (1)

    y <= %284-x%29%2F4           (2)

    x >= 0,  y >= 0      (3)


The plot below represents line (1) in red and line (2) in green.






Plot y = 6+-+2x%29%2F3 (red) and y = %284-x%29%2F4 (green).



The solution to inequality (1) is the set of all points belonging to the half plane on and below the red line (including points of this line).

The solution to inequality (2) is the set of all points belonging to the half plane on and below the green line (including points of this line).

The solution to inequality (3) is the set of all points belonging to first quadrant QI (including points of x- and y-axes).


The solution to the given system of inequalities (1), 2) and (3) is the intersection of the sets described above.


Thus the solution to the given system is the set of points belonging to the quadrilateral in QI adjacent to x- and y-axes  
which is BELOW the red line and BELOW the green line.


Again: the solution is the set of points of the quadrilateral in QI which is restrained/confined by x- and y-axes anf the red and the green lines.
All the boundaries of this quadrilateral do belong to the solution set, too.