SOLUTION: 1)graph using the intercept method 2x-5y=10 2)FIND THE SLOPE OF THE LINE PASSING THROUGH THE POINTS (-5,5) AND(-3,5)

Algebra ->  Graphs -> SOLUTION: 1)graph using the intercept method 2x-5y=10 2)FIND THE SLOPE OF THE LINE PASSING THROUGH THE POINTS (-5,5) AND(-3,5)      Log On


   

Question 111985: 1)graph using the intercept method 2x-5y=10
2)FIND THE SLOPE OF THE LINE PASSING THROUGH THE POINTS (-5,5) AND(-3,5)
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
1)


2%2Ax-5%2Ay=10 Start with the given equation

Let's find the x-intercept

To find the x-intercept, let y=0 and solve for x:
2%2Ax-5%2A%280%29=10 Plug in y=0

2%2Ax=10 Simplify

x=10%2F2 Divide both sides by 2


x=5 Reduce



So the x-intercept is (note: the x-intercept will always have a y-coordinate equal to zero)



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2%2Ax-5%2Ay=10 Start with the given equation

Now let's find the y-intercept

To find the y-intercept, let x=0 and solve for y:
2%2A%280%29-5%2Ay=10 Plug in x=0

5%2Ay=10 Simplify

x=10%2F-5 Divide both sides by -5



y=-2 Reduce



So the y-intercept is (note: the y-intercept will always have a x-coordinate equal to zero)

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So we have these intercepts:
x-intercept:

y-intercept:



Now plot the two points and




Now draw a line through the two points to graph 2%2Ax-5%2Ay=10
graph of 2%2Ax-5%2Ay=10 through the points and



2)
Solved by pluggable solver: Finding the slope


Slope of the line through the points (-5, 5) and (-3, 5)



m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29


m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+%28x%5B1%5D%29%29


m+=+%285+-+5%29%2F%28-3+-+%28-5%29%29


m+=+%285+-+5%29%2F%28-3+%2B+5%29


m+=+%280%29%2F%282%29


m+=+0



Answer: Slope is m+=+0