SOLUTION: Solve each of the following systems by substitution. 8x-4y=16 y=2x-4

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Question 111981: Solve each of the following systems by substitution.
8x-4y=16
y=2x-4
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the given system
8x-4y=16
y=2x-4



8x-4%282x-4%29=16 Plug in y=2x-4 into the first equation. In other words, replace each y with 2x-4. Notice we've eliminated the y variables. So we now have a simple equation with one unknown.


8x-8x%2B16=16 Distribute


16=16 Combine like terms on the left side


0=16-16Subtract 16 from both sides


0=0 Combine like terms on the right side


Since this equation is always true for any x value, this means x can equal any number. So there are an infinite number of solutions.