SOLUTION: 5(a)complete the table for the function f (x ) = (x^3/2)-3x -1
X |-3 |-2|-1.5|-1 |0 |1 |1.5 |2 |3 |3.5|
Y |-5.5|1 | 1.8|1.5|-1|-3.5|-3.8|-3|3.5|9.9|
b) on the
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-> SOLUTION: 5(a)complete the table for the function f (x ) = (x^3/2)-3x -1
X |-3 |-2|-1.5|-1 |0 |1 |1.5 |2 |3 |3.5|
Y |-5.5|1 | 1.8|1.5|-1|-3.5|-3.8|-3|3.5|9.9|
b) on the
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Question 1119254: 5(a)complete the table for the function f (x ) = (x^3/2)-3x -1
X |-3 |-2|-1.5|-1 |0 |1 |1.5 |2 |3 |3.5|
Y |-5.5|1 | 1.8|1.5|-1|-3.5|-3.8|-3|3.5|9.9|
b) on the grid draw the graph of y=f (x) for -3 <\=x <\=3.5
C)(i) find them inequalities for k , so that f (x) =k has only 1 answer . Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source):
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b) on the grid draw the graph of y=f (x) for -3 <\=x <\=3.5
Plot the points, draw a curve thru them.
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C)(i) find them inequalities for k , so that f (x) =k has only 1 answer
IDK what that means.
In the Figure, the plot of the function is shown.
They ask you to find the values of "k", such that each straight horizontal line y = k
intersect the plot at ONLY ONE POINT, as the most upper and the most lower horizontal straight lines do.
These values of "k" are y-values of local minimum and local maximum of the plot.
Plot y =
This question relates to Calculus, so I assume that your level is ADEQUATE to understand how to find these local maximum/minimum.
Alternatively, you can find these y-values approximately using y-values from your table.