SOLUTION: . Find the equation of the line joining the points ( 5, 1) and (-7, -7)

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Question 1115277: . Find the equation of the line joining the points ( 5, 1) and (-7, -7)
Found 3 solutions by josgarithmetic, mananth, Alan3354:
Answer by josgarithmetic(39617) About Me  (Show Source):
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y-1=%28%281-%28-7%29%29%2F%285-%28-7%29%29%29%28x-5%29


y-1=%282%2F3%29%28x-5%29-------a possible answer....

y=%282%2F3%29x-10%2F3%2B3%2F3

highlight%28y=%282%2F3%29x-7%2F3%29-------in slope-intercept form

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x1 y1 x2 y2
5 1 -7 -7

slope m = (y2-y1)/(x2-x1)
( -7 - 1 )/( -7 - 5 )
( -8 / -12 )
m= 2/3

Plug value of the slope and point ( 5 , 1 ) in
Y = m x + b
1.00 = 10/3 + b
b= 1.00 - 10/3
b= -7/3
So the equation will be
Y = 2/3 x -7/3

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the line joining the points ( 5,1) and (-7,-7)
--------
| x   y   1|
| 5   1   1| = 0
|-7  -7   1|

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x*(1+7) - y*(5+7) + 1*(-35+7) = 0
8x - 12y -28 = 0
2x - 3y = 7