Question 1110862: Determine the quadratic function f whose graph is given.
The vertex is
left parenthesis negative 3 comma negative 13 right parenthesis
(−3,−13) and the y-intercept is
negative 4.
−4.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! etermine the quadratic function f whose graph is given.
The vertex is (−3,−13) and the y-intercept is −4.
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Form:: y = ax^2+bx+c
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Since f(0) = -4, c = -4
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y = ax^2 + bx - 4
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Since vertex is at -3, -3 = -b(2a)
Since Vertex is (-3,-13), -13 = a(-3)^2 + b(-3) - 4
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Solve for "a" and for "b"::
9a - 3b = -9
-b = -6a
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3a - b = -3
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Therefore, 3a -6a = -3
-3a = -3
a = 1
Then b = 6a = 6
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Ans: y = x^2 + 6x - 4
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Cheers,
Stan H.
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