SOLUTION: Let p(x) be a nonzero polynomial with realcofficients such that P(x) =p(0)+p(1)x+p(2)x^2 holds for all x What are roots of p(x)

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Question 1110032: Let p(x) be a nonzero polynomial with realcofficients such that
P(x) =p(0)+p(1)x+p(2)x^2 holds for all x
What are roots of p(x)
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
The roots of +ax%5E2+%2B+bx+%2B+c+=+0+ can be found by the quadratic formula:
+x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F2a+
where c = p(0), b = p(1), and a = p(2), +a+%3C%3E+0+