SOLUTION: Find the x-intercepts of the graph of the equation: y = x2 - 3x + 2

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Question 1097322: Find the x-intercepts of the graph of the equation: y = x2 - 3x + 2
Found 2 solutions by rothauserc, Boreal:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
y = x^2 - 3x + 2
:
x^2 - 3x + 2 = 0
:
factor the polynomial
:
(x - 2) * (x - 1) = 0
:
1) x - 2 = 0
x = 2
:
2) x - 1 = 0
x = 1
:
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the two x axis intercepts are (2,0) and (1,0)
:
here is a graph of the equation y = x^2 - 3x + 2
:
+graph%28+300%2C+200%2C+-5%2C+5%2C+-5%2C+5%2C+x%5E2+-+3x+%2B+2%29+
:
we see that the graph of the equation crosses the x axis at
the points (1,0) and (2,0)
:
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:

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
y=x^2-3x+2=(x-2)(x-1)
when y =0, x-2=0, x=2; x-1=0, x=1
the two x-intercepts are at (1, 0) and (2, 0)
graph%28300%2C300%2C-3%2C3%2C-10%2C10%2Cx%5E2-3x%2B2%29