SOLUTION: Please help with the following: Factor: 2𝑥^2 + 11𝑥 + 15 Thank you!

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Question 1094766: Please help with the following:
Factor: 2𝑥^2 + 11𝑥 + 15
Thank you!

Found 2 solutions by ikleyn, Alan3354:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
Before making factoring, find the roots by using the quadratic formula:


x%5B1%2C2%5D = %28-11+%2B-+sqrt%2811%5E2-4%2A2%2A15%29%29%2F%282%2A2%29 = %28-11+%2B-+1%29%2F4.


x%5B1%5D = %28-11%2B1%29%2F4 = -10%2F4 = -5%2F2.

x%5B2%5D = %28-11-1%29%2F4 = -12%2F4 = -3.


It means that factoring has the form

2x%5E2+%2B+11x+%2B+15 = 2%2A%28x-%28-5%2F2%29%29%2A%28x-%28-3%29%29 =   (<<<---=== Notice that coef. 2  before the parentheses is the LEADING COEF-T of the polynomial;

                                          (the numbers (-5/2)  and  (-3) are the roots that you found above)

= 2*(x+5/2)*(x+3)}}} = (2x+5)*(x+3),


and your task is completed.

Different people use different approaches. Some try to guess the coefficients of factoring.

My personal approach is: if I can not see the factors in 5 seconds, I use the quadratic formula.

I think it is safer for my brain . . .

Other people may act differently.


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Factor: 2𝑥^2 + 11𝑥 + 15
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If you're not yet familiar with the quadratic equation, factoring is "trial & error"
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Note that all coefficients are positive.
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It has to be
(x + ?)*(2x + ?)
or
(x + a)*(2x + b)
a*b = 15
Try pairs of factors of 15
There are only 2 pair, 1*15 and 3*5
15 is greater than 11, so it's eliminated.
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So it's either
(x + 3)*(2x + 5)
or
(x + 5)*(2x + 3)