SOLUTION: Find the vertex of f(x)=-x^2-2x-8

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Question 1093316: Find the vertex of f(x)=-x^2-2x-8
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
vertex x point is at -b/2a, where b is -2 and a is -1 (writing function as ax^2+bx+c.
x=-(-2)/-1*2=-1
when x=-1, y=-1+2-8=-7
at (-1, -7)
graph%28300%2C300%2C-5%2C5%2C-10%2C10%2C-x%5E2-2x-8%29