Question 1093096: How to graph parrelle line to 3y - x = 3. Going through 2, neg 1 . Do not understand how to even graph the first one. Do not understand equation of line when x and y values are never given. I am in 7 grade. Videos never are doing same kind of problems.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The equation has to be in the form of y-mx+b; m is the slope, b the y-intercept, the value of y when x=0.
Start with 3y-x=3; I never said the equation was written wrong; I did say it had to be in a different form.
3y=x+3, moving the x to the right.
divide by 3 to make it y
y=(1/3)x+1
That means that the slope is (1/3) or rise of 1 with run of 3.
A line parallel to the line given has a slope of 1/3.
Now use the point slope formula of y-y1=m(x-x1); m is the slope and (x1,y1)=point
y is being solved for.
m is the slope, here (1/3)
(x1, y1) is the point you are given, here (2, -1)
Use this information to write
y-(-1)=(1/3)(x-2)
y+1=(1/3)x-(2/3), multiplying by (1/3)
subtract 1 (or 3/3) from both sides
y=(1/3)x-(5/3), and if x=2, that is y=(2/3)-(5/3)= -1
both lines
To graph this line, start with the -5/3. That means (0, -5/3) is one of the points.
To find another, one can move 3 to the right and up 1, but that is dealing with fractions.
Let x=3, the denominator.
y=(1/3)*3-(5/3)*3=1-5=-4
Finally, as a comment from one who has done this for over 60 years, math has many different ways to explain concepts. There is seldom one way. You asked how to graph the equation. I showed you. If it has to be done using the Saxon approach, that should be mentioned at the outset. I would have skipped the question and moved to one where perhaps I could be useful.
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