SOLUTION: 2[8-4(3-x)]-2=8[2(4x-3)+7]-50 what are the steps to solving the problem?

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Question 1087496: 2[8-4(3-x)]-2=8[2(4x-3)+7]-50
what are the steps to solving the problem?
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2[8-4(3-x)]-2=8[2(4x-3)+7]-50
what are the steps to solving the problem?
===================
Work from the inside out.
Eliminate parentheses, brackets, etc.
Combine terms.
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Assuming you want to solve for x (you should say that), isolate x on one side of the equal sign.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

2%288-4%283-x%29%29-2=8%282%284x-3%29%2B7%29-50 ...I will highlight inside parentheses
2%288-highlight%284%283-x%29%29%29-2=8%28highlight%282%284x-3%29%29%2B7%29-50...first multiply what is highlighted to eliminate parentheses
2%288-%2812-4x%29%29-2=8%28%288x-6%29%2B7%29-50...eliminate parentheses inside parentheses

highlight%282%288-12%2B4x%29%29-2=highlight%288%288x-6%2B7%29%29-50.......multiply what is highlighted
16-24%2B8x-2=64x-48%2B56-50
8x-10=64x-42
42-10=64x-8x
32=56x
x=32%2F56
x=4%2F7