SOLUTION: Solve the system of equations using the addition (elimination) method. If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answe

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Question 107970: Solve the system of equations using the addition (elimination) method.
If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
3x – 11y = 9
-9x + 33y = 18

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

3%2Ax-11%2Ay=9
-9%2Ax%2B33%2Ay=18

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 3 and -9 to some equal number, we could try to get them to the LCM.

Since the LCM of 3 and -9 is -9, we need to multiply both sides of the top equation by -3 and multiply both sides of the bottom equation by -1 like this:

-3%2A%283%2Ax-11%2Ay%29=%289%29%2A-3 Multiply the top equation (both sides) by -3
-1%2A%28-9%2Ax%2B33%2Ay%29=%2818%29%2A-1 Multiply the bottom equation (both sides) by -1


So after multiplying we get this:
-9%2Ax%2B33%2Ay=-27
9%2Ax-33%2Ay=-18

Notice how -9 and 9 and -27 and -33 add to zero (ie -9%2B9=0 33%2B-33=0)

However -27 and -18 add to -45 (ie -27%2B-18=-45);


So we're left with

0=-45


which means no value of x or y value will satisfy the system of equations. So there are no solutions


So this system is inconsistent