Question 107812: If possible please explain how you come up with each step.Thanks
Find the equation, in slope-intercept form, of the line that passes through the points (5, 6) and (-7, 3).Thanks
Found 3 solutions by checkley71, MathLover1, josmiceli:
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! SLOPE=(Y2-Y1)/(X2-X1)
SLOPE=(3-6)/(-7-5)
SLOPE=-3/-12
SLOPE=1/4 ANSWER.
NOW SUBSTITUTE ONE SET OF (X,Y) VALUES IN THE LINE EQUATUION Y=mX+b & SOLVE FOR THE Y INTERCEPT (b).
6=1/4*5+b
6=5/4+b
b=6-5/4
b=(24-5)/4
b=19/4 THIS IS THE Y INTERCEPT.
THE EQUATION IS:
Y=X/4+19/4
 (graph 300x200 pixels, x from -20 to 5, y from -10 to 10, y = x/4 +19/4).
Answer by MathLover1(20849)  (Show Source):
You can put this solution on YOUR website!
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (5, 6) and (x2, y2) = (-7, 3).
Slope a is  .
Intercept is found from equation  , or  . From that,
intercept b is  , or  .
y=(0.25)x + (4.75)
Your graph:
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Answer by josmiceli(19441)  (Show Source):
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