SOLUTION: Write an equation in slope-intercept form for the line that satisfies the following condition.passes through (29,8) perpendicular to the graph of y=1/13x+17

Algebra ->  Graphs -> SOLUTION: Write an equation in slope-intercept form for the line that satisfies the following condition.passes through (29,8) perpendicular to the graph of y=1/13x+17      Log On


   

Question 1075223: Write an equation in slope-intercept form for the line that satisfies the following condition.passes through (29,8) perpendicular to the graph of y=1/13x+17
Found 2 solutions by Boreal, josgarithmetic:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of the line is 1/13; the perpendicular line has slope -13, the negative reciprocal.
point slope
y-y1=m(x-x1), x1, y1 are point, m the slope
y-8=-13(x-29)
y-8=-13x+377
y=-13x+385

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx+b
b=y-mx
Slope NEEDED is -13.

y=-13x%2B%288-%28-13%2929%29