You can put this solution on YOUR website! The diagonals of a parallelogram bisect each other.
that means that the midpoint of AC is also the midpoint of BD.
Thee coordinates of the midpoint of a segment
are the averages of the corresponding coordinates
of the endpoints of the segment.
The midpoint of AC is ((2+(-1))/2,(0+1)/2) = (1/2,1/2) .
The midpoint of BD is ((p+3)/2,(-2+r)/2) .
So <--> <--> <--> ,
and <--> <--> <--> .