SOLUTION: Find the equation for the line that passed through the point (2,3), and that is perpendicular to the line with the equation -1/2x+2y"-13/2

Algebra ->  Graphs -> SOLUTION: Find the equation for the line that passed through the point (2,3), and that is perpendicular to the line with the equation -1/2x+2y"-13/2      Log On


   

Question 1070830: Find the equation for the line that passed through the point (2,3), and that is perpendicular to the line with the equation -1/2x+2y"-13/2
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
-1/2x+2y"-13/2
You mean, -%281%2F2%29x%2B2y=13%2F2 ?
What is the slope? Put into slope-intercept form if necessary.
2y=x%2F2-13%2F2
y=x%2F4-13%2F4
and slope of the given equation would be 1%2F4.

A line perpendicular to it would have slope m so that %281%2F4%29%2Am=-1,
m=-4.

The line with this slope of -4 passing through point (2,3) if put into the point-slope form is y-3=-4%28x-2%29,
and if wanted in the slope-intercept form,
y=-4%28x-2%29%2B3
y=-4x%2B8%2B3
highlight%28y=-4x%2B11%29-----line perpendicular to -%281%2F2%29x%2B2y=13%2F2 and containing point (2,3).


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In case your double-quote mark on the y was meant as "second derivative", then none of the above solution counts.