SOLUTION: X^2-6x+y^2+10y=-18 rewritten as the equation of a circle is A. (X-3)^2+(y+5)^2=9^2 B. X^2-6x+18=-y^2-10y C. (X-3)+(y+5)^2=4^2 D. (X^2-3)+(y^2+5)=16

Algebra ->  Graphs -> SOLUTION: X^2-6x+y^2+10y=-18 rewritten as the equation of a circle is A. (X-3)^2+(y+5)^2=9^2 B. X^2-6x+18=-y^2-10y C. (X-3)+(y+5)^2=4^2 D. (X^2-3)+(y^2+5)=16      Log On


   

Question 1070744: X^2-6x+y^2+10y=-18 rewritten as the equation of a circle is
A. (X-3)^2+(y+5)^2=9^2
B. X^2-6x+18=-y^2-10y
C. (X-3)+(y+5)^2=4^2
D. (X^2-3)+(y^2+5)=16
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
X^2-6x+y^2+10y=-18
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Complete the squares for x and for y.
(x^2-6x) + (y^2+10y) = -18