SOLUTION: Solve the following system. Y=(1/2)x^2 + 2x - 1 and 3x - y = 1 The solutions are ( ) and ( )

Algebra ->  Graphs -> SOLUTION: Solve the following system. Y=(1/2)x^2 + 2x - 1 and 3x - y = 1 The solutions are ( ) and ( )       Log On


   

Question 1063680: Solve the following system.
Y=(1/2)x^2 + 2x - 1 and 3x - y = 1
The solutions are ( ) and ( )
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Y=(1/2)x^2 + 2x - 1
3x - y = 1, or y=3x-1
substitute
3x-1=(1/2)x^2+2x-1
0=(1/2)x^2-x
0=x(0.5x-1)
x=0,2
y=2+4-1=5
3(2)-1=5.
When x=2 y=5 (2,5) is one solution
when x=0, y=-1, (0,-1) is the other solution