SOLUTION: Find all the points on the x-axis that are a distance of 13 units from (12,5).

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Question 1043671: Find all the points on the x-axis that are a distance of 13 units from (12,5).
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

All points on the x-axis have their y-coordinates equal to 0.
So let the point (a,0) be a point on the x-axis such that the
distance from (12,5) to (a,0) is 13 units:

Use the distance formula:

d=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29

%2812-a%29%5E2%2B%285-0%29%5E2=13

Square both sides:

%2812-a%29%5E2%2B5%5E2=13%5E2

%2812-a%29%5E2%2B25=169

(((12-a)^2=144}}}

Take square roots of both sides

12-a=%22%22+%2B-+12

Using the +

12-a=12

-a=0

a=0

Using the -

12-a=-12

-a=-24

a=24

There are exactly two points, substituting in (a,0),

they are (0,0), and (24,0)




Edwin