SOLUTION: A ball with a camera is thrown up in the air by a person who released it at a height of 1.7m. The ball's sensor took pictures a its maximum height of 33m. The ball was not caught

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Question 1042711: A ball with a camera is thrown up in the air by a person who released it at a height of 1.7m. The ball's sensor took pictures a its maximum height of 33m.
The ball was not caught and hit the ground at 4.8 seconds after the time it was released.
Sketch a graph that would model the ball's height versus time. and state the type of function and any key features related to the graph.
Thanks for your time.
Found 2 solutions by josmiceli, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Use the free-fall equation in meters
+h%28t%29+=+-%281%2F2%29%2A9.8t%5E2+%2B+v%5B0%5D%2At+%2B+h%5B0%5D+
+h%5B0%5D+=+1.7+
+h%28t%29+=+-4.9t%5E2+%2B+v%5B0%5D%2At+%2B+1.7+
-------------------
The formula for the t-value of the vertex is:
+t%5Bv%5D+=+-b%2F%282a%29+
+a+=+-4.9+
+b+=+v%5B0%5D+
+t%5Bv%5D+=+-v%5B0%5D%2F%282%28-4.9%29%29+
+t%5Bv%5D+=+v%5B0%5D+%2F+9.8+
------------------------
You are given that:
+h%28t%29+=+-4.9t%5E2+%2B+v%5B0%5D%2At+%2B+1.7+
When the ball hits the ground:
+0+=+-4.9t%5E2+%2B+v%5B0%5D%2At+%2B+1.7+
+t+=+4.8+
+0+=+-4.9%2A4.8%5E2+%2B+v%5B0%5D%2A4.8+%2B+1.7+
+0+=+-4.9%2A23.04+%2B+4.8%2Av%5B0%5D+%2B+1.7+
+0+=+-112.896+%2B+1.7+%2B+4.8v%5B0%5D+
+4.8v%5B0%5D+=+111.196+
+v%5B0%5D+=+23.1658+
--------------------
+t%5Bv%5D+=+v%5B0%5D+%2F+9.8+
+t%5Bv%5D+=+23.1658+%2F+9.8+
+t%5Bv%5D+=+2.36386+
-------------------
the equation is:
+h%28t%29+=+-4.9t%5E2+%2B+23.1658t+%2B+1.7+
+h%5Bv%5D+=+-4.9%2A2.36386%5E2+%2B+23.1658%2A2.36386+%2B+1.7+
--------------------------------------------
here's the plot:
+h%5Bv%5D+=+-27.3804+%2B+54.7607+%2B+1.7+
+h%5Bv%5D+=+29.0803+
+graph%28+600%2C+600%2C+-1%2C+7%2C+-5%2C+35%2C+-4.9x%5E2+%2B+23.1658x+%2B+1.7+%29+
The maximum height looks correct -I'd get a 2nd
opinion on this if possible

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
You have to give the acceleration of gravity.
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Don't expect someone else to assume it.