SOLUTION: I know how to graph and substitute but I just can't figure out this "if" statements, I have no clue on what to do here: Let h be the function which is the set of all ordered pai

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Question 1040558: I know how to graph and substitute but I just can't figure out this "if" statements, I have no clue on what to do here:
Let h be the function which is the set of all ordered pairs (x,y) such that:
Y= x+5 if x ≤ - 3
Y= √9-x^2 if -3 ≤ x ≤ 3
Y= 5-x if 3 < 3
I tried solving the first one, I used -4,-5,-6,-7,-8 as my x (assuming that I'm correct with the "if" part) I computed it and y became -1,0,-1,-2,-3 .Is this correct?
Also with number 2 , I have no idea how to do that one. Please help me.

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The function consists of three different parts along the x-axis.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
I know how to graph and substitute but I just can't figure out this "if" statements, I have no clue on what to do here:
Let h be the function which is the set of all ordered pairs (x,y) such that:
Y= x+5 if x ≤ - 3
Y= √9-x^2 if -3 ≤ x ≤ 3
Y= 5-x if highlight%28x+%3E+3%29         ( <--- notice I fixed your typo in this point! )
I tried solving the first one, I used -4,-5,-6,-7,-8 as my x (assuming that I'm correct with the "if" part)
I computed it and y became -1,0,-1,-2,-3. Is this correct?
Also with number 2 , I have no idea how to do that one. Please help me.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1.  You are absolutely right with your calculations for -4, -5, -6, -7, -8.

2.  Let's consider x = 2.
    You should look in which of the three intervals lies this number.
    "2" lies between -3 and 3, correct?

    Hence, f(x) = sqrt%289-x%5E2%29 = sqrt%289-%28-2%29%5E2%29 = sqrt%289-4%29 = sqrt%285%29.

3.  All other cases are subject of the same logic.