SOLUTION: y = -x*2/8 + 11x/8 + 3/2 Find the equation of the axis of symmetry, explaining your method. Use this information to find the coordinates of the vertex, giving your answers to on

Algebra ->  Graphs -> SOLUTION: y = -x*2/8 + 11x/8 + 3/2 Find the equation of the axis of symmetry, explaining your method. Use this information to find the coordinates of the vertex, giving your answers to on      Log On


   

Question 1040100: y = -x*2/8 + 11x/8 + 3/2
Find the equation of the axis of symmetry, explaining your method. Use this information to find the coordinates of the vertex, giving your answers to one decimal place.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
y = -x*2/8 + 11x/8 + 3/2
Find the equation of the axis of symmetry, explaining your method. Use this information to find the coordinates of the vertex, giving your answers to one decimal place.
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y = -x^2/8 + 11x/8 + 3/2 ---- Use ^ (Shift 6) for exponents.
* --> multiply
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f(x) = -x^2/8 + 11x/8 + 3/2
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AOS is x = -b/2a = (-11/8)/(-1/4)
x = 11/2
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Vertex is (11/2,f(11/2))
f(11/2) = -121/32 + 121/16 + 3/2 = 169/32
Vertex (11/2,169/32)