SOLUTION: Zmax=8x1+16x2 subject to x1+x2<200 3x1+6x2<900 x2=125 x1 x2>0

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Question 1027394: Zmax=8x1+16x2
subject to
x1+x2<200
3x1+6x2<900
x2=125
x1 x2>0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Your constraints are given so that the lines are not included as part of the solution.
When you substitute x%5B2%5D=125
x%5B1%5D%2B125%3C200
x%5B1%5D%3C75
.
.
3x%5B1%5D%2B6%28125%29%3C900
3x%5B1%5D%2B750%3C900
3x%5B1%5D%3C150
x%5B1%5D%3C50
.
.
So then,
Z%5Bmax%5D=8x%5B1%5D%2B6%28125%29
Z%5Bmax%5D=8x%5B1%5D%2B750
Since you don't have an equal sign, you can't get an exact value for the maximum Z value.
You can state,
Z%5Bmax%5D%3C8%2850%29%2B750
Z%5Bmax%5D%3C400%2B750
Z%5Bmax%5D%3C1150