SOLUTION: Please someone help me i am lost as to howto do this. Identify the axis of symmetry, create a suitable table of values, then sketch the graph including the axis of symmetry. {{{y=

Algebra ->  Graphs -> SOLUTION: Please someone help me i am lost as to howto do this. Identify the axis of symmetry, create a suitable table of values, then sketch the graph including the axis of symmetry. {{{y=      Log On


   

Question 102739: Please someone help me i am lost as to howto do this.
Identify the axis of symmetry, create a suitable table of values, then sketch the graph including the axis of symmetry. y=x%5E2%2B2
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
First, to "create a suitable table of values" simply means to assign a value to the indepedent variable (that's x) and, using the given equation, find the coressponding value of the dependent variable (that's y) and make a table of these.
You don't say how many entries are required but 4 or 5 should suffice. Be sure to include value of x that show where the parabola intersect the x-axis, if this is applicable. (this will be true when y = 0)
To see if there are any x-intersects, set y = o and solve for x.
y+=+x%5E2%2B2 Set y = 0
0+=+x%5E2%2B2 Subtract 2 from both sides.
-2+=+x%5E2 Take the square root of both sides.
x+=+sqrt%28-2%29 or x+=+-sqrt%28-2%29 As you can see, the x's are imaginary values x+=+sqrt%282%29i or x+=+-sqrt%282%29i so the parabola does not intersect the x-axis.
Here are a few values for the table.
x..(x^2+2)
0....2
1....3
2....6
3...11
4...18
Heres what the graph looks like:
graph%28600%2C400%2C-6%2C6%2C-4%2C25%2Cx%5E2%2B2%29
You can see the axis of symmetry on the graph...it's x = 0