SOLUTION: Graph the following equation using the intercept method. If a line goes through the origin, select an additional point. Plot a third point as a check. y+3x=0 I need to graph

Algebra ->  Graphs -> SOLUTION: Graph the following equation using the intercept method. If a line goes through the origin, select an additional point. Plot a third point as a check. y+3x=0 I need to graph       Log On


   



Question 1027147: Graph the following equation using the intercept method. If a line goes through the origin, select an additional point. Plot a third point as a check.
y+3x=0
I need to graph this line and find the x intercept, y intercept, and an additional point as a check. I would appreciate it SO very much if someone could help me! Thank you!!

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y+3x=0
y = -3x
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I need to graph this line and find the x intercept, y intercept, and an additional point as a check. I would appreciate it SO very much if someone could help me! Thank you!!
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y-int:: Let x = 0, then y = 0 :: Ans: (0,0)
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x-int:: Let y = 0, then x = 0 :: Ans: (0,0)
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Additional point:: Let x = 2, they y = -6 ;; Point (2,-6)
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graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C-3x%29
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Cheers,
Stan H.
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