Question 1026912: Find the point(s) on the graph of x^2+y^2=45 at which the slope of the tangent is -1/2.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the point(s) on the graph of x^2+y^2=45 at which the slope of the tangent is -1/2.
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slope m = -x/y
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-x/y = -1/2
y = 2x
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x^2+y^2=45
x^2+(2x)^2=45
5x^2 = 45
x^2 = 9
x = +3, y = 6 --> (3,6)
x = -3, y = 6 --> (-3,6)
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