SOLUTION: What is the slope and y-intercept of the line whose equation is given. Then graph the linear function. y=2x+1 I do not understand this at all! Could someone please help me? I w

Algebra ->  Graphs -> SOLUTION: What is the slope and y-intercept of the line whose equation is given. Then graph the linear function. y=2x+1 I do not understand this at all! Could someone please help me? I w      Log On


   



Question 102504This question is from textbook Essentials of Intermediate Algebra for college students
: What is the slope and y-intercept of the line whose equation is given. Then graph the linear function. y=2x+1
I do not understand this at all! Could someone please help me? I would greatly appreciate it. Thanks So Much.
This question is from textbook Essentials of Intermediate Algebra for college students

Found 2 solutions by stanbon, doukungfoo:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the slope and y-intercept of the line whose equation is given. Then graph the linear function. y=2x+1
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The slope is 2; the y-intercept is 1
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Graph:
graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C2x%2B1%29
Cheers,
Stan H.

Answer by doukungfoo(195) About Me  (Show Source):
You can put this solution on YOUR website!
First you have to know what the slope intercept form of the equation of a line is. It looks like this:
y = mx + b
m is the slope of the line and
b is the y intercept
When we compare it to the equation we are given
y = 2x + 1
we can see that the equation we are given is already in slope intercept form and we can easily identify the slope and y intercept.
y = mx + b
y = 2x + 1
So the 2 is in the m's place. That means that the slope of this line is 2 or more correctly 2/1
There is a 1 in the b's place. That means that the y intercept for this line is at positive 1 on the y axis.
Now lets put the line on a graph.
We know the line crosses the y axis at positive 1 so put a dot there. Now the slope is 2/1 so rise up 2 and run over to the right 1. Put a dot here at point (1,3) now take a ruler or straight edge and line up the two dots and draw your line. Like this.
+graph%28+500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+2x%2B1%29+