SOLUTION: I'm having a hard time graphing this circle. I know to plot (8,-3) it's where to plot the radius is where I'm having the biggest trouble: (x-8)^2 + (y+3)^2=4

Algebra ->  Graphs -> SOLUTION: I'm having a hard time graphing this circle. I know to plot (8,-3) it's where to plot the radius is where I'm having the biggest trouble: (x-8)^2 + (y+3)^2=4      Log On


   



Question 1015487: I'm having a hard time graphing this circle. I know to plot (8,-3) it's where to plot the radius is where I'm having the biggest trouble:
(x-8)^2 + (y+3)^2=4

Found 3 solutions by Alan3354, macston, Boreal:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(x-8)^2 + (y+3)^2=4
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r^2 = 4
radius = 2

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-8%29%5E2%2B%28y%2B3%29%5E2=4
Center at (8, -3) radius=2
The point (8,-3) is not plotted: it is the center, not on the circle.
The radius is not plotted: it is the distance from center to the circle.
Four points will be:
(6,-3) (2 units (radius) left of center)
(10,-3) (2 units (radius) right of center)
(8,-5) (2 units (radius) below center)
(8,-1) (2 units (radius) above center)
The circle goes through these four points.
The circle is all points 2 units away from the center.
.

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
The radius is is 2, since it is the square root of 4.
Center is (8,-3) as you have stated.
The quadrants will be at (6,-3)(10,-3) on the line y=-3
The other two are at (8,-5) and (8,-1) on the line x=8