SOLUTION: Find the area of the rectangle whose vertices are the points with coordinates (5,2),(5,-6),(0,-6),and (0,2).

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Question 1003842: Find the area of the rectangle whose vertices are the points with coordinates (5,2),(5,-6),(0,-6),and (0,2).
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
the rectangle whose vertices are the points with coordinates:
(5,2),(5,-6),(0,-6),and (0,2)



as you can see, the length of the rectangle is the distance between the points (0,2) and (0,-6)
and the width is the distance between the points (0,2) and (5,2)
the length L is:
Solved by pluggable solver: Distance between two points in two dimensions
The distance (denoted by d) between two points in two dimensions is given by the following formula:

d=sqrt%28%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2%29

Thus in our case, the required distance is
d=sqrt%28%280-0%29%5E2+%2B+%282--6%29%5E2%29=+8+


For more on this concept, refer to Distance formula.



the width is W:
Solved by pluggable solver: Distance between two points in two dimensions
The distance (denoted by d) between two points in two dimensions is given by the following formula:

d=sqrt%28%28x1-x2%29%5E2+%2B+%28y1-y2%29%5E2%29

Thus in our case, the required distance is
d=sqrt%28%280-5%29%5E2+%2B+%282-2%29%5E2%29=+5+


For more on this concept, refer to Distance formula.


L=8
W=5
so, the area is:A=LW=>A=8%2A5=>A=40